What is the answer to solvefor x,sqrt(2x)-5y=-1 ?

The answer to solvefor x,sqrt(2x)-5y=-1 is x=(1-10y+25y^2)/2 {y>= 1/5 }

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solvefor x,sqrt(2x)-5y=-1

solve for

x, 2 x - 5 y = - 1

x = \frac{1 - 10 y + 25 y ^{2}}{2} {y \geq \frac{1}{5}}

Solution steps

2 x - 5 y = - 1

Move

5 y

to the right side

2 x = - 1 + 5 y

Square both sides:

2 x = 1 - 10 y + 25 y^{2}

2 x = 1 - 10 y + 25 y^{2}

Solve

2 x = 1 - 10 y + 25 y^{2} : x = \frac{1 - 10 y + 25 y ^{2}}{2}

x = \frac{1 - 10 y + 25 y ^{2}}{2}

Verify Solutions:

x = \frac{1 - 10 y + 25 y ^{2}}{2} {y \geq \frac{1}{5}}

The solution is

x = \frac{1 - 10 y + 25 y ^{2}}{2} {y \geq \frac{1}{5}}

3 x + 1 = 0

x + 4 = 7

5 x + 1 = 6

2 x + 15 - 2 = 0

3 - x = 3 x + 7 + 2

What is the answer to solvefor x,sqrt(2x)-5y=-1 ?
The answer to solvefor x,sqrt(2x)-5y=-1 is x=(1-10y+25y^2)/2 {y>= 1/5 }