What is the answer to solvefor a,b=sqrt(1-a^2) ?

The answer to solvefor a,b=sqrt(1-a^2) is a=sqrt(-b^2+1) {0<= b<= 1},a=-sqrt(-b^2+1) {0<= b<= 1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,b=sqrt(1-a^2)

solve for

a, b = 1 - a^{2}

a = - b^{2} + 1 {0 \leq b \leq 1}, a = - - b^{2} + 1 {0 \leq b \leq 1}

Solution steps

b = 1 - a^{2}

Square both sides:

b^{2} = 1 - a^{2}

b^{2} = 1 - a^{2}

Solve

b^{2} = 1 - a^{2} : a = - b^{2} + 1, a = - - b^{2} + 1

a = - b^{2} + 1, a = - - b^{2} + 1

Verify Solutions:

a = - b^{2} + 1 {0 \leq b \leq 1}, a = - - b^{2} + 1 {0 \leq b \leq 1}

The solutions are

a = - b^{2} + 1 {0 \leq b \leq 1}, a = - - b^{2} + 1 {0 \leq b \leq 1}

2 x - 3 = 3 - x

x + 9 - 4 = 1

19 x + 24 = - 5 x

1.96 \frac{2.45}{n} = 1.6

What is the answer to solvefor a,b=sqrt(1-a^2) ?
The answer to solvefor a,b=sqrt(1-a^2) is a=sqrt(-b^2+1) {0<= b<= 1},a=-sqrt(-b^2+1) {0<= b<= 1}