What is the answer to sqrt(2x+1)=1+sqrt(x) ?

The answer to sqrt(2x+1)=1+sqrt(x) is x=4,x=0

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sqrt(2x+1)=1+sqrt(x)

2 x + 1 = 1 + x

x = 4, x = 0

Solution steps

2 x + 1 = 1 + x

Remove square roots

x^{2} = 4 x

Solve

x^{2} = 4 x : x = 4, x = 0

x = 4, x = 0

Verify Solutions:

x = 4

True

, x = 0

True

The solutions are

x = 4, x = 0

3 x + 7 = 2 x

\frac{x}{x ^{2} - 1} = 0

x^{\frac{1}{3}} = - 3

5 = 22 + 0.06 t^{2}

3 - x = 1 + x - 2

What is the answer to sqrt(2x+1)=1+sqrt(x) ?
The answer to sqrt(2x+1)=1+sqrt(x) is x=4,x=0
Solve for x: sqrt(2x+1)=1+sqrt(x)
The solution is x=4,x=0