What is the answer to sqrt(x+2\sqrt{2x+3)}-4=0 ?

The answer to sqrt(x+2\sqrt{2x+3)}-4=0 is x=2(10-sqrt(39))

Solve for x: sqrt(x+2\sqrt{2x+3)}-4=0

The solution is x=2(10-sqrt(39))

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x + 2 2 x + 3 - 4 = 0

x = 2 (10 - 39)

Decimal Notation

x = 7.51000 \dots

Solution steps

x + 2 2 x + 3 - 4 = 0

Move

4

to the right side

x + 2 2 x + 3 = 4

Remove square roots

8 x + 12 = 256 - 32 x + x^{2}

Solve

8 x + 12 = 256 - 32 x + x^{2} : x = 2 (10 + 39), x = 2 (10 - 39)

x = 2 (10 + 39), x = 2 (10 - 39)

Verify Solutions:

x = 2 (10 + 39)

False

, x = 2 (10 - 39)

True

The solution is

x = 2 (10 - 39)

u + 8 = 6

5 x - 20 = 0

b = 1 + 7 - 3 b

5 x - 4 = 9 x - 2

What is the answer to sqrt(x+2\sqrt{2x+3)}-4=0 ?
The answer to sqrt(x+2\sqrt{2x+3)}-4=0 is x=2(10-sqrt(39))
Solve for x: sqrt(x+2\sqrt{2x+3)}-4=0
The solution is x=2(10-sqrt(39))