What is the answer to sqrt(3y+1)-1=sqrt(y+4) ?

The answer to sqrt(3y+1)-1=sqrt(y+4) is y=5

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sqrt(3y+1)-1=sqrt(y+4)

3 y + 1 - 1 = y + 4

y = 5

Solution steps

3 y + 1 - 1 = y + 4

Remove square roots

12 y + 4 = 4 y^{2} - 8 y + 4

Solve

12 y + 4 = 4 y^{2} - 8 y + 4 : y = 5, y = 0

y = 5, y = 0

Verify Solutions:

y = 5

True

, y = 0

False

The solution is

y = 5

2 x + 7 = x + 2

6 - x^{2} = 4 - x^{2}

11 = 12 b - 59

x - 5 + x = 5

3 = 11 - (4 - 6 x)^{\frac{1}{2}}

What is the answer to sqrt(3y+1)-1=sqrt(y+4) ?
The answer to sqrt(3y+1)-1=sqrt(y+4) is y=5
Solve for y: sqrt(3y+1)-1=sqrt(y+4)
The solution is y=5