What is the answer to \sqrt[4]{x^2-9x}=0 ?

The answer to \sqrt[4]{x^2-9x}=0 is x=9,x=0

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\sqrt[4]{x^2-9x}=0

x = 9, x = 0

Solution steps

Take both sides of the equation to the power of

4 : x^{2} - 9 x = 0

x^{2} - 9 x = 0

Solve

x^{2} - 9 x = 0 : x = 9, x = 0

x = 9, x = 0

Verify Solutions:

x = 9

True

, x = 0

True

The solutions are

x = 9, x = 0

x - 1 2 x + 6 = x + 3

x^{2} + 48 = 8

\frac{3 x}{x - 6} = 3

x - 13 = 5 - x + 2

What is the answer to \sqrt[4]{x^2-9x}=0 ?
The answer to \sqrt[4]{x^2-9x}=0 is x=9,x=0
Solve for x: \sqrt[4]{x^2-9x}=0
The solution is x=9,x=0