What are the solutions to the equation 3x^2+14x+5=0 ?

The solutions to the equation 3x^2+14x+5=0 are x=(-7+sqrt(34))/3 ,x=-(7+sqrt(34))/3

Find the zeros of 3x^2+14x+5=0

The zeros of 3x^2+14x+5=0 are x=(-7+sqrt(34))/3 ,x=-(7+sqrt(34))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 14 x + 5 = 0

x = \frac{- 7 + 34}{3}, x = - \frac{7 + 34}{3}

Decimal Notation

x = - 0.38968 \dots, x = - 4.27698 \dots

Solution steps

3 x^{2} + 14 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 5 = 234

x_{1, 2} = \frac{- 14 \pm 2 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 2 34}{2 \cdot 3}, x_{2} = \frac{- 14 - 2 34}{2 \cdot 3}

x = \frac{- 14 + 2 34}{2 \cdot 3} : \frac{- 7 + 34}{3}

x = \frac{- 14 - 2 34}{2 \cdot 3} : - \frac{7 + 34}{3}

The solutions to the quadratic equation are:

x = \frac{- 7 + 34}{3}, x = - \frac{7 + 34}{3}

3 x - 15 + 2 x - 14 = x - 11

3 x^{2} - 8 x - 3 = 0

\frac{3}{2} x^{- \frac{1}{2}}

e^{4} = y

4 + \frac{3}{4}

What are the solutions to the equation 3x^2+14x+5=0 ?
The solutions to the equation 3x^2+14x+5=0 are x=(-7+sqrt(34))/3 ,x=-(7+sqrt(34))/3
Find the zeros of 3x^2+14x+5=0
The zeros of 3x^2+14x+5=0 are x=(-7+sqrt(34))/3 ,x=-(7+sqrt(34))/3