What is the answer to sqrt(x^4)=(sqrt(x+7))^2 ?

The answer to sqrt(x^4)=(sqrt(x+7))^2 is x=(1+sqrt(29))/2 ,x=(1-sqrt(29))/2

Solve for x: sqrt(x^4)=(sqrt(x+7))^2

The solution is x=(1+sqrt(29))/2 ,x=(1-sqrt(29))/2

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x^{4} = (x + 7)^{2}

x = \frac{1 + 29}{2}, x = \frac{1 - 29}{2}

Decimal Notation

x = 3.19258 \dots, x = - 2.19258 \dots

Solution steps

x^{4} = (x + 7)^{2}

Square both sides:

x^{4} = (x + 7)^{2}

x^{4} = (x + 7)^{2}

Solve

x^{4} = (x + 7)^{2} : x = \frac{1 + 29}{2}, x = \frac{1 - 29}{2}

x = \frac{1 + 29}{2}, x = \frac{1 - 29}{2}

Verify Solutions:

x = \frac{1 + 29}{2}

True

, x = \frac{1 - 29}{2}

True

The solutions are

x = \frac{1 + 29}{2}, x = \frac{1 - 29}{2}

x^{2} = 1

4 x = 2 3 - x

3 - 2 x = 7

12 x^{4} - 96 x^{\frac{13}{4}} = 0

x + 3 2 - x = 4

What is the answer to sqrt(x^4)=(sqrt(x+7))^2 ?
The answer to sqrt(x^4)=(sqrt(x+7))^2 is x=(1+sqrt(29))/2 ,x=(1-sqrt(29))/2
Solve for x: sqrt(x^4)=(sqrt(x+7))^2
The solution is x=(1+sqrt(29))/2 ,x=(1-sqrt(29))/2