What is the answer to -sqrt(x^2-2x-15)=x+1 ?

The answer to -sqrt(x^2-2x-15)=x+1 is x=-4

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-sqrt(x^2-2x-15)=x+1

- x^{2} - 2 x - 15 = x + 1

x = - 4

Solution steps

- x^{2} - 2 x - 15 = x + 1

Square both sides:

x^{2} - 2 x - 15 = x^{2} + 2 x + 1

x^{2} - 2 x - 15 = x^{2} + 2 x + 1

Solve

x^{2} - 2 x - 15 = x^{2} + 2 x + 1 : x = - 4

x = - 4

Verify Solutions:

x = - 4

True

The solution is

x = - 4

1 - 2 x + x + 8 = 5

8 t + 9 = - 9

3 - 3 x - 1 = 2 x

20 = 2 π \frac{l}{32}

2 (x - 5)^{\frac{2}{3}} = 32

What is the answer to -sqrt(x^2-2x-15)=x+1 ?
The answer to -sqrt(x^2-2x-15)=x+1 is x=-4
Solve for x: -sqrt(x^2-2x-15)=x+1
The solution is x=-4