What are the solutions to the equation -16t^2+128t+1680=0 ?

The solutions to the equation -16t^2+128t+1680=0 are t=-7,t=15

Find the zeros of -16t^2+128t+1680=0

The zeros of -16t^2+128t+1680=0 are t=-7,t=15

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- 16 t^{2} + 128 t + 1680 = 0

t = - 7, t = 15

Solution steps

- 16 t^{2} + 128 t + 1680 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 128 \pm 12 8 ^{2} - 4 ( - 16 ) \cdot 1680}{2 ( - 16 )}

12 8^{2} - 4 (- 16) \cdot 1680 = 352

t_{1, 2} = \frac{- 128 \pm 352}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 128 + 352}{2 ( - 16 )}, t_{2} = \frac{- 128 - 352}{2 ( - 16 )}

t = \frac{- 128 + 352}{2 ( - 16 )} : - 7

t = \frac{- 128 - 352}{2 ( - 16 )} : 15

The solutions to the quadratic equation are:

t = - 7, t = 15

∣ x + 6 ∣ = 2

x^{2} + (x + 7)^{2} = 1 3^{2}

- ∣ 2 x + 4 ∣ = - 6

12 m - 8 = - 42 m + 100

2 x + 127 = 3 x + 54

What are the solutions to the equation -16t^2+128t+1680=0 ?
The solutions to the equation -16t^2+128t+1680=0 are t=-7,t=15
Find the zeros of -16t^2+128t+1680=0
The zeros of -16t^2+128t+1680=0 are t=-7,t=15