What is the answer to \sqrt[4]{39-2x}=\sqrt[4]{2x-9} ?

The answer to \sqrt[4]{39-2x}=\sqrt[4]{2x-9} is x=12

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\sqrt[4]{39-2x}=\sqrt[4]{2x-9}

x = 12

Solution steps

Take both sides of the equation to the power of

4 : 39 - 2 x = 2 x - 9

39 - 2 x = 2 x - 9

Solve

39 - 2 x = 2 x - 9 : x = 12

x = 12

Verify Solutions:

x = 12

True

The solution is

x = 12

4 x - 15 x + 14 = 0

10 + 9 x + 7 x + 8 = 2

5 x = 40 x^{- \frac{1}{2}}

x - 12 - 4 x = 0

What is the answer to \sqrt[4]{39-2x}=\sqrt[4]{2x-9} ?
The answer to \sqrt[4]{39-2x}=\sqrt[4]{2x-9} is x=12
Solve for x: \sqrt[4]{39-2x}=\sqrt[4]{2x-9}
The solution is x=12