What is the answer to solvefor w,z=sqrt(w^2+9) ?

The answer to solvefor w,z=sqrt(w^2+9) is w=sqrt(z^2-9) {z>= 3},w=-sqrt(z^2-9) {z>= 3}

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solvefor w,z=sqrt(w^2+9)

solve for

w, z = w^{2} + 9

w = z^{2} - 9 {z \geq 3}, w = - z^{2} - 9 {z \geq 3}

Solution steps

z = w^{2} + 9

Square both sides:

z^{2} = w^{2} + 9

z^{2} = w^{2} + 9

Solve

z^{2} = w^{2} + 9 : w = z^{2} - 9, w = - z^{2} - 9

w = z^{2} - 9, w = - z^{2} - 9

Verify Solutions:

w = z^{2} - 9 {z \geq 3}, w = - z^{2} - 9 {z \geq 3}

The solutions are

w = z^{2} - 9 {z \geq 3}, w = - z^{2} - 9 {z \geq 3}

x - 2 = - 3 x + 76

x - 8 x x = 0

7 x - 19 = x - 1

2 x = 0

- 28 + 11 x = x

What is the answer to solvefor w,z=sqrt(w^2+9) ?
The answer to solvefor w,z=sqrt(w^2+9) is w=sqrt(z^2-9) {z>= 3},w=-sqrt(z^2-9) {z>= 3}