What is the answer to \sqrt[3]{x^3-3x^2+12}=x ?

The answer to \sqrt[3]{x^3-3x^2+12}=x is x=2,x=-2

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\sqrt[3]{x^3-3x^2+12}=x

x = 2, x = - 2

Solution steps

Take both sides of the equation to the power of

3 : x^{3} - 3 x^{2} + 12 = x^{3}

x^{3} - 3 x^{2} + 12 = x^{3}

Solve

x^{3} - 3 x^{2} + 12 = x^{3} : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

3 x - 22 = - x + 10

x + 8 = x + 6

x = 9 x

5 x + 9 = 35

2 x = 16 x - 64

What is the answer to \sqrt[3]{x^3-3x^2+12}=x ?
The answer to \sqrt[3]{x^3-3x^2+12}=x is x=2,x=-2
Solve for x: \sqrt[3]{x^3-3x^2+12}=x
The solution is x=2,x=-2