What are the solutions to the equation x^2-2x=22 ?

The solutions to the equation x^2-2x=22 are x=1+sqrt(23),x=1-sqrt(23)

Find the zeros of x^2-2x=22

The zeros of x^2-2x=22 are x=1+sqrt(23),x=1-sqrt(23)

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x^{2} - 2 x = 22

x = 1 + 23, x = 1 - 23

Decimal Notation

x = 5.79583 \dots, x = - 3.79583 \dots

Solution steps

x^{2} - 2 x = 22

Move

22

to the left side

x^{2} - 2 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 22) = 223

x_{1, 2} = \frac{- ( - 2 ) \pm 2 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 23}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 23}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 23}{2 \cdot 1} : 1 + 23

x = \frac{- ( - 2 ) - 2 23}{2 \cdot 1} : 1 - 23

The solutions to the quadratic equation are:

x = 1 + 23, x = 1 - 23

12 x^{2} - 36 x

- 2 ∣ 2 x + 1 ∣ + 7 = 1

\frac{4}{x ^{2} + 9} > 0

\frac{10}{11} - \frac{1}{2}

8 x^{2} - 14 x - 15 = 0

What are the solutions to the equation x^2-2x=22 ?
The solutions to the equation x^2-2x=22 are x=1+sqrt(23),x=1-sqrt(23)
Find the zeros of x^2-2x=22
The zeros of x^2-2x=22 are x=1+sqrt(23),x=1-sqrt(23)