What is the answer to sqrt(-x^2+2x+1)=x ?

The answer to sqrt(-x^2+2x+1)=x is x=(1+sqrt(3))/2

Solve for x: sqrt(-x^2+2x+1)=x

The solution is x=(1+sqrt(3))/2

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- x^{2} + 2 x + 1 = x

x = \frac{1 + 3}{2}

Decimal Notation

x = 1.36602 \dots

Solution steps

- x^{2} + 2 x + 1 = x

Square both sides:

- x^{2} + 2 x + 1 = x^{2}

- x^{2} + 2 x + 1 = x^{2}

Solve

- x^{2} + 2 x + 1 = x^{2} : x = - \frac{- 1 + 3}{2}, x = \frac{1 + 3}{2}

x = - \frac{- 1 + 3}{2}, x = \frac{1 + 3}{2}

Verify Solutions:

x = - \frac{- 1 + 3}{2}

False

, x = \frac{1 + 3}{2}

True

The solution is

x = \frac{1 + 3}{2}

5 x - 6 = 3 x + 4

3 = 3 x - 8 + 1

\frac{x}{x ^{2} + 1} = 0

x = x + 1

What is the answer to sqrt(-x^2+2x+1)=x ?
The answer to sqrt(-x^2+2x+1)=x is x=(1+sqrt(3))/2
Solve for x: sqrt(-x^2+2x+1)=x
The solution is x=(1+sqrt(3))/2