What is the answer to \sqrt[5]{x^2-18x}=-2 ?

The answer to \sqrt[5]{x^2-18x}=-2 is x=16,x=2

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\sqrt[5]{x^2-18x}=-2

x = 16, x = 2

Solution steps

Take both sides of the equation to the power of

5 : x^{2} - 18 x = - 32

x^{2} - 18 x = - 32

Solve

x^{2} - 18 x = - 32 : x = 16, x = 2

x = 16, x = 2

Verify Solutions:

x = 16

True

, x = 2

True

The solutions are

x = 16, x = 2

2 x + 3 - x = 2

x + 8 - x + 2 = 1

x + 8 = 2 x + 5

100 q = 2 q + 1200

What is the answer to \sqrt[5]{x^2-18x}=-2 ?
The answer to \sqrt[5]{x^2-18x}=-2 is x=16,x=2
Solve for x: \sqrt[5]{x^2-18x}=-2
The solution is x=16,x=2