What is the answer to solvefor y,x=y^{-1/3} ?

The answer to solvefor y,x=y^{-1/3} is y= 1/(x^3) {x 0}

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solvefor y,x=y^{-1/3}

solve for

y, x = y^{- \frac{1}{3}}

y = \frac{1}{x ^{3}} {x < 0 or x > 0}

Solution steps

x = y^{- \frac{1}{3}}

Take both sides of the equation to the power of

- 3 : \frac{1}{x ^{3}} = y

\frac{1}{x ^{3}} = y

Switch sides

y = \frac{1}{x ^{3}}

Verify Solutions:

y = \frac{1}{x ^{3}} {x < 0 or x > 0}

The solution is

y = \frac{1}{x ^{3}} {x < 0 or x > 0}

y, x + 2 y = z

(2 x + 1)^{0.3} = x - 4

x - 1 - x = - 3

3 x + 1 - 2 x - 1 = 4

12 + 4 x = x

What is the answer to solvefor y,x=y^{-1/3} ?
The answer to solvefor y,x=y^{-1/3} is y= 1/(x^3) {x<0\lor x>0}