What is the answer to \sqrt[4]{12x^2-32}=x ?

The answer to \sqrt[4]{12x^2-32}=x is x=2sqrt(2),x=2

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\sqrt[4]{12x^2-32}=x

x = 22, x = 2

Decimal Notation

x = 2.82842 \dots, x = 2

Solution steps

Take both sides of the equation to the power of

4 : 12 x^{2} - 32 = x^{4}

12 x^{2} - 32 = x^{4}

Solve

12 x^{2} - 32 = x^{4} : x = 22, x = - 22, x = 2, x = - 2

x = 22, x = - 22, x = 2, x = - 2

Verify Solutions:

x = 22

True

, x = - 22

False

, x = 2

True

, x = - 2

False

The solutions are

x = 22, x = 2

(u - 10)^{\frac{4}{5}} = 2

x = - x + 6

b = - 4 + 4 b

(x^{2} + 14 x)^{\frac{1}{5}} = 2

6 x + 27 = x

What is the answer to \sqrt[4]{12x^2-32}=x ?
The answer to \sqrt[4]{12x^2-32}=x is x=2sqrt(2),x=2
Solve for x: \sqrt[4]{12x^2-32}=x
The solution is x=2sqrt(2),x=2