What is the answer to x^2+1+3sqrt(x^2+1)=28 ?

The answer to x^2+1+3sqrt(x^2+1)=28 is x=sqrt(15),x=-sqrt(15)

Solve for x: x^2+1+3sqrt(x^2+1)=28

The solution is x=sqrt(15),x=-sqrt(15)

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x^{2} + 1 + 3 x^{2} + 1 = 28

x = 15, x = - 15

Decimal Notation

x = 3.87298 \dots, x = - 3.87298 \dots

Solution steps

x^{2} + 1 + 3 x^{2} + 1 = 28

Remove square roots

9 x^{2} + 9 = x^{4} - 54 x^{2} + 729

Solve

9 x^{2} + 9 = x^{4} - 54 x^{2} + 729 : x = 43, x = - 43, x = 15, x = - 15

x = 43, x = - 43, x = 15, x = - 15

Verify Solutions:

x = 43

False

, x = - 43

False

, x = 15

True

, x = - 15

True

The solutions are

x = 15, x = - 15

5 = a^{\frac{3}{5}}

r + 5 = 11

x - 4 = 19 x + 16

\frac{a x + b - 2}{x} = 1

w = 3

What is the answer to x^2+1+3sqrt(x^2+1)=28 ?
The answer to x^2+1+3sqrt(x^2+1)=28 is x=sqrt(15),x=-sqrt(15)
Solve for x: x^2+1+3sqrt(x^2+1)=28
The solution is x=sqrt(15),x=-sqrt(15)