What is the answer to 4x=2sqrt(2x)+20sqrt(2) ?

The answer to 4x=2sqrt(2x)+20sqrt(2) is x=(20sqrt(2)+1+sqrt(1+40\sqrt{2)})/4

Solve for x: 4x=2sqrt(2x)+20sqrt(2)

The solution is x=(20sqrt(2)+1+sqrt(1+40\sqrt{2)})/4

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4 x = 2 2 x + 202

x = \frac{20 2 + 1 + 1 + 40 2}{4}

Decimal Notation

x = 9.21791 \dots

Solution steps

4 x = 2 2 x + 202

Remove square roots

16 x^{2} - 1602 x + 800 = 8 x

Solve

16 x^{2} - 1602 x + 800 = 8 x : x = \frac{20 2 + 1 + 1 + 40 2}{4}, x = \frac{20 2 + 1 - 1 + 40 2}{4}

x = \frac{20 2 + 1 + 1 + 40 2}{4}, x = \frac{20 2 + 1 - 1 + 40 2}{4}

Verify Solutions:

x = \frac{20 2 + 1 + 1 + 40 2}{4}

True

, x = \frac{20 2 + 1 - 1 + 40 2}{4}

False

The solution is

x = \frac{20 2 + 1 + 1 + 40 2}{4}

5 x - 4 = x

2 x + 2 = 7 x + 2

x^{2} - 3 = 2 x

314 = 6 x

x, x = x - 2

What is the answer to 4x=2sqrt(2x)+20sqrt(2) ?
The answer to 4x=2sqrt(2x)+20sqrt(2) is x=(20sqrt(2)+1+sqrt(1+40\sqrt{2)})/4
Solve for x: 4x=2sqrt(2x)+20sqrt(2)
The solution is x=(20sqrt(2)+1+sqrt(1+40\sqrt{2)})/4