What is the answer to x+sqrt(2x^2+x+9)=3 ?

The answer to x+sqrt(2x^2+x+9)=3 is x=0,x=-7

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x+sqrt(2x^2+x+9)=3

x + 2 x^{2} + x + 9 = 3

x = 0, x = - 7

Solution steps

x + 2 x^{2} + x + 9 = 3

Remove square roots

2 x^{2} + x + 9 = 9 - 6 x + x^{2}

Solve

2 x^{2} + x + 9 = 9 - 6 x + x^{2} : x = 0, x = - 7

x = 0, x = - 7

Verify Solutions:

x = 0

True

, x = - 7

True

The solutions are

x = 0, x = - 7

6 x - 11 + 4 = 12 x + 1

4 p + 1 - 7 = 0

40 - 6 x = 2 x

x - 2 - x = 0

(x - 5)^{\frac{3}{4}} - 27 = 0

What is the answer to x+sqrt(2x^2+x+9)=3 ?
The answer to x+sqrt(2x^2+x+9)=3 is x=0,x=-7
Solve for x: x+sqrt(2x^2+x+9)=3
The solution is x=0,x=-7