What are the solutions to the equation 2x^2-6x+2=0 ?

The solutions to the equation 2x^2-6x+2=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

Find the zeros of 2x^2-6x+2=0

The zeros of 2x^2-6x+2=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 6 x + 2 = 0

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Decimal Notation

x = 2.61803 \dots, x = 0.38196 \dots

Solution steps

2 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 \cdot 2 = 25

x_{1, 2} = \frac{- ( - 6 ) \pm 2 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 5}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 5}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 5}{2 \cdot 2} : \frac{3 + 5}{2}

x = \frac{- ( - 6 ) - 2 5}{2 \cdot 2} : \frac{3 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

(3 - 4 x) (3 x - 7) \geq 0

x^{2} (2 x)

(3 - 3)^{2}

2 \cdot 4^{\frac{3}{2}}

1000 \cdot 9.8

What are the solutions to the equation 2x^2-6x+2=0 ?
The solutions to the equation 2x^2-6x+2=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2
Find the zeros of 2x^2-6x+2=0
The zeros of 2x^2-6x+2=0 are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2