What is the answer to (a^2+1)^{1/2}=a+1 ?

The answer to (a^2+1)^{1/2}=a+1 is a=0

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(a^2+1)^{1/2}=a+1

(a^{2} + 1)^{\frac{1}{2}} = a + 1

a = 0

Solution steps

(a^{2} + 1)^{\frac{1}{2}} = a + 1

Square both sides:

a^{2} + 1 = a^{2} + 2 a + 1

a^{2} + 1 = a^{2} + 2 a + 1

Solve

a^{2} + 1 = a^{2} + 2 a + 1 : a = 0

a = 0

Verify Solutions:

a = 0

True

The solution is

a = 0

z + 7 = 6

x^{2} - 2 x + 4 = 2 x - 2

45 = 5 (- 1 - 7 p)^{\frac{2}{3}}

- 4 x - 3 = 12

What is the answer to (a^2+1)^{1/2}=a+1 ?
The answer to (a^2+1)^{1/2}=a+1 is a=0
Solve for a: (a^2+1)^{1/2}=a+1
The solution is a=0