What is the answer to sqrt(4x^2-4x+1)=x-1 ?

The answer to sqrt(4x^2-4x+1)=x-1 is No Solution for x\in\mathbb{R}

Solve for x: sqrt(4x^2-4x+1)=x-1

The solution is No Solution for x\in\mathbb{R}

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4 x^{2} - 4 x + 1 = x - 1

No Solution for x \in R

Solution steps

4 x^{2} - 4 x + 1 = x - 1

Square both sides:

4 x^{2} - 4 x + 1 = x^{2} - 2 x + 1

4 x^{2} - 4 x + 1 = x^{2} - 2 x + 1

Solve

4 x^{2} - 4 x + 1 = x^{2} - 2 x + 1 : x = \frac{2}{3}, x = 0

x = \frac{2}{3}, x = 0

Verify Solutions:

x = \frac{2}{3}

False

, x = 0

False

The solution is

No Solution for x \in R

4 x - 4 = x - 1

x^{2} - 5 x + 1 + x^{2} - 5 x = 1

3 x + 31 = x + 7

y, x = 6 - y

2 a - 5 = 10 - a

What is the answer to sqrt(4x^2-4x+1)=x-1 ?
The answer to sqrt(4x^2-4x+1)=x-1 is No Solution for x\in\mathbb{R}
Solve for x: sqrt(4x^2-4x+1)=x-1
The solution is No Solution for x\in\mathbb{R}