What is the answer to sqrt(2x^3-3x^2-11x+6)=0 ?

The answer to sqrt(2x^3-3x^2-11x+6)=0 is x=-2,x= 1/2 ,x=3

Solve for x: sqrt(2x^3-3x^2-11x+6)=0

The solution is x=-2,x= 1/2 ,x=3

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2 x^{3} - 3 x^{2} - 11 x + 6 = 0

x = - 2, x = \frac{1}{2}, x = 3

Decimal Notation

x = - 2, x = 0.5, x = 3

Solution steps

2 x^{3} - 3 x^{2} - 11 x + 6 = 0

Square both sides:

2 x^{3} - 3 x^{2} - 11 x + 6 = 0

2 x^{3} - 3 x^{2} - 11 x + 6 = 0

Solve

2 x^{3} - 3 x^{2} - 11 x + 6 = 0 : x = - 2, x = \frac{1}{2}, x = 3

x = - 2, x = \frac{1}{2}, x = 3

Verify Solutions:

x = - 2

True

, x = \frac{1}{2}

True

, x = 3

True

The solutions are

x = - 2, x = \frac{1}{2}, x = 3

x - 48 = 8 - x

2 x + 14 = 16

y^{\frac{1}{4}} = 3

x - 5 + 7 = x - 3

y, x = 2 y + 1

What is the answer to sqrt(2x^3-3x^2-11x+6)=0 ?
The answer to sqrt(2x^3-3x^2-11x+6)=0 is x=-2,x= 1/2 ,x=3
Solve for x: sqrt(2x^3-3x^2-11x+6)=0
The solution is x=-2,x= 1/2 ,x=3