What is the answer to sqrt(3x+7)+sqrt(x+1)=2 ?

The answer to sqrt(3x+7)+sqrt(x+1)=2 is x=-1

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sqrt(3x+7)+sqrt(x+1)=2

3 x + 7 + x + 1 = 2

x = - 1

Solution steps

3 x + 7 + x + 1 = 2

Remove square roots

4 x^{2} + 8 x + 4 = 16 x + 16

Solve

4 x^{2} + 8 x + 4 = 16 x + 16 : x = 3, x = - 1

x = 3, x = - 1

Verify Solutions:

x = 3

False

, x = - 1

True

The solution is

x = - 1

x = - \frac{1}{2}

24 - 5 x = x - 6

6 x^{\frac{2}{3}} = 216

x - 5 x - 19 = 5

n^{\frac{3}{2}} = 125

What is the answer to sqrt(3x+7)+sqrt(x+1)=2 ?
The answer to sqrt(3x+7)+sqrt(x+1)=2 is x=-1
Solve for x: sqrt(3x+7)+sqrt(x+1)=2
The solution is x=-1