What is ((x^2yz)^2xy)/((xy^2)^3z^2) ?

The solution to ((x^2yz)^2xy)/((xy^2)^3z^2) is (x^2)/(y^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((x^2yz)^2xy)/((xy^2)^3z^2)

simplify

\frac{( x ^{2} yz ) ^{2} x y}{( x y ^{2} ) ^{3} z ^{2}}

\frac{x ^{2}}{y ^{3}}

Solution steps

\frac{( x ^{2} yz ) ^{2} x y}{( x y ^{2} ) ^{3} z ^{2}}

Simplify

(x^{2} yz)^{2} : x^{4} y^{2} z^{2}

= \frac{x ^{4} y ^{2} z ^{2} x y}{( x y ^{2} ) ^{3} z ^{2}}

Simplify

(x y^{2})^{3} : x^{3} y^{6}

= \frac{x ^{4} y ^{2} z ^{2} x y}{x ^{3} y ^{6} z ^{2}}

Simplify

\frac{x ^{4}}{x ^{3}} : x

= \frac{x y ^{2} z ^{2} x y}{y ^{6} z ^{2}}

Cancel the common factor:

z^{2}

= \frac{x y ^{2} x y}{y ^{6}}

Simplify

\frac{y ^{2}}{y ^{6}} : \frac{1}{y ^{4}}

= \frac{xx y}{y ^{4}}

Simplify

\frac{y}{y ^{4}} : \frac{1}{y ^{3}}

= \frac{xx}{y ^{3}}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{x ^{2}}{y ^{3}}

- 2 x + 7 = 4

- 18 + 2 x = x + 15

\frac{5}{12} m - \frac{1}{8} m = \frac{1}{3}

x^{2} - 16 x + 64

∣ x ∣ > - 5

What is ((x^2yz)^2xy)/((xy^2)^3z^2) ?
The solution to ((x^2yz)^2xy)/((xy^2)^3z^2) is (x^2)/(y^3)