What is the answer to solvefor x,x+y=sqrt(2(xy+3)) ?

The answer to solvefor x,x+y=sqrt(2(xy+3)) is x=sqrt(6-y^2),x=-sqrt(6-y^2)

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solvefor x,x+y=sqrt(2(xy+3))

solve for

x, x + y = 2 (x y + 3)

x = 6 - y^{2}, x = - 6 - y^{2}

Solution steps

x + y = 2 (x y + 3)

Square both sides:

x^{2} + 2 x y + y^{2} = 2 x y + 6

x^{2} + 2 x y + y^{2} = 2 x y + 6

Solve

x^{2} + 2 x y + y^{2} = 2 x y + 6 : x = 6 - y^{2}, x = - 6 - y^{2}

x = 6 - y^{2}, x = - 6 - y^{2}

Verify Solutions:

x = 6 - y^{2}

True

, x = - 6 - y^{2}

True

The solutions are

x = 6 - y^{2}, x = - 6 - y^{2}

(x - 1)^{\frac{7}{5}} = 128

x + 3 + 4 - x = - 3

x + 10 - 9 = - 7

5 x + 11 = 9

x = x

What is the answer to solvefor x,x+y=sqrt(2(xy+3)) ?
The answer to solvefor x,x+y=sqrt(2(xy+3)) is x=sqrt(6-y^2),x=-sqrt(6-y^2)