What is the answer to (1+x)^{15.6}=2 ?

The answer to (1+x)^{15.6}=2 is x=2^{5/78}-1

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(1+x)^{15.6}=2

(1 + x)^{15.6} = 2

x = 2^{\frac{5}{78}} - 1

Decimal Notation

x = 0.04543 \dots

Solution steps

(1 + x)^{15.6} = 2

Take both sides of the equation to the power of

\frac{5}{78} : (1 + x) = 2^{\frac{5}{78}}

(1 + x) = 2^{\frac{5}{78}}

Solve

(1 + x) = 2^{\frac{5}{78}} : x = 2^{\frac{5}{78}} - 1

x = 2^{\frac{5}{78}} - 1

Verify Solutions:

x = 2^{\frac{5}{78}} - 1

True

The solution is

x = 2^{\frac{5}{78}} - 1

a, ma - N = r

22 = 4 x

m + 2 = m + 12

x + 7 + x = 3

4 x = 15 x^{2} + 5 x + 14

What is the answer to (1+x)^{15.6}=2 ?
The answer to (1+x)^{15.6}=2 is x=2^{5/78}-1
Solve for x: (1+x)^{15.6}=2
The solution is x=2^{5/78}-1