What is the answer to sqrt(19x^2-13-3)=2x+1 ?

The answer to sqrt(19x^2-13-3)=2x+1 is x=(2+sqrt(259))/(15)

Solve for x: sqrt(19x^2-13-3)=2x+1

The solution is x=(2+sqrt(259))/(15)

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19 x^{2} - 13 - 3 = 2 x + 1

x = \frac{2 + 259}{15}

Decimal Notation

x = 1.20623 \dots

Solution steps

19 x^{2} - 13 - 3 = 2 x + 1

Square both sides:

19 x^{2} - 16 = 4 x^{2} + 4 x + 1

19 x^{2} - 16 = 4 x^{2} + 4 x + 1

Solve

19 x^{2} - 16 = 4 x^{2} + 4 x + 1 : x = - \frac{- 2 + 259}{15}, x = \frac{2 + 259}{15}

x = - \frac{- 2 + 259}{15}, x = \frac{2 + 259}{15}

Verify Solutions:

x = - \frac{- 2 + 259}{15}

False

, x = \frac{2 + 259}{15}

True

The solution is

x = \frac{2 + 259}{15}

x = 11 x - 18

75 = x^{2} + (- 0.15 x)^{2}

4 2 x + 1 - 7 = 1

- 4 = 2 - y^{2} - 4 y + 15

What is the answer to sqrt(19x^2-13-3)=2x+1 ?
The answer to sqrt(19x^2-13-3)=2x+1 is x=(2+sqrt(259))/(15)
Solve for x: sqrt(19x^2-13-3)=2x+1
The solution is x=(2+sqrt(259))/(15)