What is the answer to solvefor A,2sqrt(A)+6B=25 ?

The answer to solvefor A,2sqrt(A)+6B=25 is A= 625/4-75B+9B^2 {B<= 25/6 }

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solvefor A,2sqrt(A)+6B=25

solve for

A, 2 A + 6 B = 25

A = \frac{625}{4} - 75 B + 9 B^{2} {B \leq \frac{25}{6}}

Solution steps

2 A + 6 B = 25

Move

6 B

to the right side

2 A = 25 - 6 B

Divide both sides by

2

A = \frac{25 - 6 B}{2}

Square both sides:

A = \frac{625}{4} - 75 B + 9 B^{2}

A = \frac{625}{4} - 75 B + 9 B^{2}

Verify Solutions:

A = \frac{625}{4} - 75 B + 9 B^{2} {B \leq \frac{25}{6}}

The solution is

A = \frac{625}{4} - 75 B + 9 B^{2} {B \leq \frac{25}{6}}

22 x - 55 = x + 3

64 x^{2} - 156 - 4 x = 0

x + x + x = 1

x^{2} + 5 x + 20 = 4

2 x - 7 = 13

What is the answer to solvefor A,2sqrt(A)+6B=25 ?
The answer to solvefor A,2sqrt(A)+6B=25 is A= 625/4-75B+9B^2 {B<= 25/6 }