What is the answer to solvefor y,x=sqrt(-y^2) ?

The answer to solvefor y,x=sqrt(-y^2) is y=sqrt(-x^2) {x=0},y=-sqrt(-x^2) {x=0}

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solvefor y,x=sqrt(-y^2)

solve for

y, x = - y^{2}

y = - x^{2} {x = 0}, y = - - x^{2} {x = 0}

Solution steps

x = - y^{2}

Square both sides:

x^{2} = - y^{2}

x^{2} = - y^{2}

Solve

x^{2} = - y^{2} : y = - x^{2}, y = - - x^{2}

y = - x^{2}, y = - - x^{2}

Verify Solutions:

y = - x^{2} {x = 0}, y = - - x^{2} {x = 0}

The solutions are

y = - x^{2} {x = 0}, y = - - x^{2} {x = 0}

2 x^{2} - 4 = x

4 t + 9 = - 5

3 x - 2 - x + 2 = 4

x + 4 + x - 4 = 4

4 - b = b

What is the answer to solvefor y,x=sqrt(-y^2) ?
The answer to solvefor y,x=sqrt(-y^2) is y=sqrt(-x^2) {x=0},y=-sqrt(-x^2) {x=0}