What are the solutions to the equation 9x^2-6x+82=0 ?

The solutions to the equation 9x^2-6x+82=0 are x= 1/3+3i,x= 1/3-3i

Find the zeros of 9x^2-6x+82=0

The zeros of 9x^2-6x+82=0 are x= 1/3+3i,x= 1/3-3i

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9 x^{2} - 6 x + 82 = 0

x = \frac{1}{3} + 3 i, x = \frac{1}{3} - 3 i

Solution steps

9 x^{2} - 6 x + 82 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 82}{2 \cdot 9}

Simplify

(- 6)^{2} - 4 \cdot 9 \cdot 82 : 54 i

x_{1, 2} = \frac{- ( - 6 ) \pm 54 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 54 i}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 54 i}{2 \cdot 9}

x = \frac{- ( - 6 ) + 54 i}{2 \cdot 9} : \frac{1}{3} + 3 i

x = \frac{- ( - 6 ) - 54 i}{2 \cdot 9} : \frac{1}{3} - 3 i

The solutions to the quadratic equation are:

x = \frac{1}{3} + 3 i, x = \frac{1}{3} - 3 i

- 8 x^{5} y^{3} (- 3 x^{3} y^{3})

\frac{10 x - 5 z}{14 x ^{2} + 5 x z - z ^{2}}

\frac{( 2 x ^{2} y ^{2} ) ^{- 3}}{( 2 x ^{2} y ^{2} ) ^{- 4}}

x^{2} + 5 x - 66 = 0

3 a^{2} + 7 ab + 2 b^{2}

What are the solutions to the equation 9x^2-6x+82=0 ?
The solutions to the equation 9x^2-6x+82=0 are x= 1/3+3i,x= 1/3-3i
Find the zeros of 9x^2-6x+82=0
The zeros of 9x^2-6x+82=0 are x= 1/3+3i,x= 1/3-3i