What is the answer to 3x+sqrt(3-2x)=2 ?

The answer to 3x+sqrt(3-2x)=2 is x= 1/9

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3x+sqrt(3-2x)=2

3 x + 3 - 2 x = 2

x = \frac{1}{9}

Decimal Notation

x = 0.11111 \dots

Solution steps

3 x + 3 - 2 x = 2

Remove square roots

3 - 2 x = 4 - 12 x + 9 x^{2}

Solve

3 - 2 x = 4 - 12 x + 9 x^{2} : x = 1, x = \frac{1}{9}

x = 1, x = \frac{1}{9}

Verify Solutions:

x = 1

False

, x = \frac{1}{9}

True

The solution is

x = \frac{1}{9}

x + 2 = 2 x - 9 + 4

y, x = 64 - y^{2}

25 x = \frac{x ^{2}}{25}

20 + x = x

2 x - 1 + x + 4 = 0