What are the solutions to the equation 5w(5w+12)=-32 ?

The solutions to the equation 5w(5w+12)=-32 are w=-4/5 ,w=-8/5

Find the zeros of 5w(5w+12)=-32

The zeros of 5w(5w+12)=-32 are w=-4/5 ,w=-8/5

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5 w (5 w + 12) = - 32

w = - \frac{4}{5}, w = - \frac{8}{5}

Decimal Notation

w = - 0.8, w = - 1.6

Solution steps

5 w (5 w + 12) = - 32

Expand

5 w (5 w + 12) : 25 w^{2} + 60 w

25 w^{2} + 60 w = - 32

Move

32

to the left side

25 w^{2} + 60 w + 32 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 25 \cdot 32}{2 \cdot 25}

6 0^{2} - 4 \cdot 25 \cdot 32 = 20

w_{1, 2} = \frac{- 60 \pm 20}{2 \cdot 25}

Separate the solutions

w_{1} = \frac{- 60 + 20}{2 \cdot 25}, w_{2} = \frac{- 60 - 20}{2 \cdot 25}

w = \frac{- 60 + 20}{2 \cdot 25} : - \frac{4}{5}

w = \frac{- 60 - 20}{2 \cdot 25} : - \frac{8}{5}

The solutions to the quadratic equation are:

w = - \frac{4}{5}, w = - \frac{8}{5}

y, 3 x + 4 y = 12

18 x^{2} - 2

\frac{7}{2} > \frac{1 - 4 x}{5} > \frac{3}{2}

x^{3} - 25 x > 0

12 x^{2} + 28 x + 8

What are the solutions to the equation 5w(5w+12)=-32 ?
The solutions to the equation 5w(5w+12)=-32 are w=-4/5 ,w=-8/5
Find the zeros of 5w(5w+12)=-32
The zeros of 5w(5w+12)=-32 are w=-4/5 ,w=-8/5