What is the answer to 2=sqrt(1^2+y^2) ?

The answer to 2=sqrt(1^2+y^2) is y=sqrt(3),y=-sqrt(3)

Solve for y: 2=sqrt(1^2+y^2)

The solution is y=sqrt(3),y=-sqrt(3)

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Popular >

2 = 1^{2} + y^{2}

y = 3, y = - 3

Decimal Notation

y = 1.73205 \dots, y = - 1.73205 \dots

Solution steps

2 = 1^{2} + y^{2}

Square both sides:

4 = 1 + y^{2}

4 = 1 + y^{2}

Solve

4 = 1 + y^{2} : y = 3, y = - 3

y = 3, y = - 3

Verify Solutions:

y = 3

True

, y = - 3

True

The solutions are

y = 3, y = - 3

x = 5 + x + 1

3 x + 7 = 5 x + 1

a + 5 = 4

4 x - 3 + 2 = 7

56 = 7 x - 10

What is the answer to 2=sqrt(1^2+y^2) ?
The answer to 2=sqrt(1^2+y^2) is y=sqrt(3),y=-sqrt(3)
Solve for y: 2=sqrt(1^2+y^2)
The solution is y=sqrt(3),y=-sqrt(3)