What is the answer to 5=sqrt((a+2)^2+(-2+5)^2) ?

The answer to 5=sqrt((a+2)^2+(-2+5)^2) is a=2,a=-6

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5=sqrt((a+2)^2+(-2+5)^2)

5 = (a + 2)^{2} + (- 2 + 5)^{2}

a = 2, a = - 6

Solution steps

5 = (a + 2)^{2} + (- 2 + 5)^{2}

Square both sides:

25 = a^{2} + 4 a + 13

25 = a^{2} + 4 a + 13

Solve

25 = a^{2} + 4 a + 13 : a = 2, a = - 6

a = 2, a = - 6

Verify Solutions:

a = 2

True

, a = - 6

True

The solutions are

a = 2, a = - 6

x^{2} = - 1

x - 20 = 0

x^{\frac{3}{5}} = - 64

5 x - 1 - x = 1

10 - 13 x = x - 4

What is the answer to 5=sqrt((a+2)^2+(-2+5)^2) ?
The answer to 5=sqrt((a+2)^2+(-2+5)^2) is a=2,a=-6
Solve for a: 5=sqrt((a+2)^2+(-2+5)^2)
The solution is a=2,a=-6