What is ((9r^3a^2+6r^2a^2-27r))/(3r^2a) ?

The solution to ((9r^3a^2+6r^2a^2-27r))/(3r^2a) is (3r^2a^2+2ra^2-9)/(ra)

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simplify ((9r^3a^2+6r^2a^2-27r))/(3r^2a)

simplify

\frac{( 9 r ^{3} a ^{2} + 6 r ^{2} a ^{2} - 27 r )}{3 r ^{2} a}

\frac{3 r ^{2} a ^{2} + 2 r a ^{2} - 9}{r a}

Solution steps

\frac{9 r ^{3} a ^{2} + 6 r ^{2} a ^{2} - 27 r}{3 r ^{2} a}

Factor

9 r^{3} a^{2} + 6 r^{2} a^{2} - 27 r : 3 r (3 r^{2} a^{2} + 2 r a^{2} - 9)

= \frac{3 r ( 3 r ^{2} a ^{2} + 2 r a ^{2} - 9 )}{3 r ^{2} a}

Cancel the common factor:

3

= \frac{r ( 3 r ^{2} a ^{2} + 2 r a ^{2} - 9 )}{r ^{2} a}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

r^{2} = rr

= \frac{r ( 3 r ^{2} a ^{2} + 2 r a ^{2} - 9 )}{rr a}

Cancel the common factor:

r

= \frac{3 r ^{2} a ^{2} + 2 r a ^{2} - 9}{r a}

\frac{- 8}{2}

3 > 2 x - 5 \geq 7

x^{2} - 12 x + 11

(4^{\frac{1}{2}})^{2}

∣ x ∣ = x^{2} + x - 3

What is ((9r^3a^2+6r^2a^2-27r))/(3r^2a) ?
The solution to ((9r^3a^2+6r^2a^2-27r))/(3r^2a) is (3r^2a^2+2ra^2-9)/(ra)