What is the answer to \sqrt[3]{x^3-2x^2+8}=x ?

The answer to \sqrt[3]{x^3-2x^2+8}=x is x=2,x=-2

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\sqrt[3]{x^3-2x^2+8}=x

x = 2, x = - 2

Solution steps

Take both sides of the equation to the power of

3 : x^{3} - 2 x^{2} + 8 = x^{3}

x^{3} - 2 x^{2} + 8 = x^{3}

Solve

x^{3} - 2 x^{2} + 8 = x^{3} : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

y = \frac{y ^{2}}{8}

(x - 2)^{\frac{1}{4}} = 2

4 x = 16 x

y = y - 2

2 = \frac{1 + 29 - 4 x}{- 3}

What is the answer to \sqrt[3]{x^3-2x^2+8}=x ?
The answer to \sqrt[3]{x^3-2x^2+8}=x is x=2,x=-2
Solve for x: \sqrt[3]{x^3-2x^2+8}=x
The solution is x=2,x=-2