What is the answer to solvefor y,x=\sqrt[3]{y}+2 ?

The answer to solvefor y,x=\sqrt[3]{y}+2 is y=x^3-6x^2+12x-8

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solvefor y,x=\sqrt[3]{y}+2

solve for

y = x^{3} - 6 x^{2} + 12 x - 8

Solution steps

Switch sides

Move

2

to the right side

Take both sides of the equation to the power of

3 : y = x^{3} - 6 x^{2} + 12 x - 8

y = x^{3} - 6 x^{2} + 12 x - 8

Verify Solutions:

y = x^{3} - 6 x^{2} + 12 x - 8

True

The solution is

y = x^{3} - 6 x^{2} + 12 x - 8

x - 2 = 9 x + 4

6 = 1.5 h

(x - 5)^{\frac{5}{2}} = 32

9 x + 4 = 7 x + 1 + 1

y = y^{2}

What is the answer to solvefor y,x=\sqrt[3]{y}+2 ?
The answer to solvefor y,x=\sqrt[3]{y}+2 is y=x^3-6x^2+12x-8