What is the answer to \sqrt[3]{6-s^2}+5=0 ?

The answer to \sqrt[3]{6-s^2}+5=0 is s=sqrt(131),s=-sqrt(131)

Solve for s: \sqrt[3]{6-s^2}+5=0

The solution is s=sqrt(131),s=-sqrt(131)

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s = 131, s = - 131

Decimal Notation

s = 11.44552 \dots, s = - 11.44552 \dots

Solution steps

Move

5

to the right side

Take both sides of the equation to the power of

3 : 6 - s^{2} = - 125

6 - s^{2} = - 125

Solve

6 - s^{2} = - 125 : s = 131, s = - 131

s = 131, s = - 131

Verify Solutions:

s = 131

True

, s = - 131

True

The solutions are

s = 131, s = - 131

34 - 6 n + 7 = n

2 y - 5 = 4

a, 45 (ab) = 30 - a

x = x + 1

What is the answer to \sqrt[3]{6-s^2}+5=0 ?
The answer to \sqrt[3]{6-s^2}+5=0 is s=sqrt(131),s=-sqrt(131)
Solve for s: \sqrt[3]{6-s^2}+5=0
The solution is s=sqrt(131),s=-sqrt(131)