What is the answer to cube root of 4x-2}=2\sqrt[3]{x+6 ?

The answer to cube root of 4x-2}=2\sqrt[3]{x+6 is x=-25/2

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cube root of 4x-2}=2\sqrt[3]{x+6

x = - \frac{25}{2}

Decimal Notation

x = - 12.5

Solution steps

Take both sides of the equation to the power of

3 : 4 x - 2 = 8 x + 48

4 x - 2 = 8 x + 48

Solve

4 x - 2 = 8 x + 48 : x = - \frac{25}{2}

x = - \frac{25}{2}

Verify Solutions:

x = - \frac{25}{2}

True

The solution is

x = - \frac{25}{2}

x = x + 3

24 - 6 x = x + 8

y, x = y - 4

What is the answer to cube root of 4x-2}=2\sqrt[3]{x+6 ?
The answer to cube root of 4x-2}=2\sqrt[3]{x+6 is x=-25/2
Solve for x: cube root of 4x-2}=2\sqrt[3]{x+6
The solution is x=-25/2