What is the answer to sqrt(2x^2-4x+9)=2x-3 ?

The answer to sqrt(2x^2-4x+9)=2x-3 is x=4

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sqrt(2x^2-4x+9)=2x-3

2 x^{2} - 4 x + 9 = 2 x - 3

x = 4

Solution steps

2 x^{2} - 4 x + 9 = 2 x - 3

Square both sides:

2 x^{2} - 4 x + 9 = 4 x^{2} - 12 x + 9

2 x^{2} - 4 x + 9 = 4 x^{2} - 12 x + 9

Solve

2 x^{2} - 4 x + 9 = 4 x^{2} - 12 x + 9 : x = 0, x = 4

x = 0, x = 4

Verify Solutions:

x = 0

False

, x = 4

True

The solution is

x = 4

x - 11 x x = 0

16 x^{2} + 2 = 4 x + 1

2 x + 36 + 6 = x

x + 2 x - 1 = 2 (x - 3)^{2}

x 8 x + 1 = 5

What is the answer to sqrt(2x^2-4x+9)=2x-3 ?
The answer to sqrt(2x^2-4x+9)=2x-3 is x=4
Solve for x: sqrt(2x^2-4x+9)=2x-3
The solution is x=4