What is the answer to sqrt(2x-3)-sqrt(x+1)=1 ?

The answer to sqrt(2x-3)-sqrt(x+1)=1 is x=7+2sqrt(7)

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sqrt(2x-3)-sqrt(x+1)=1

2 x - 3 - x + 1 = 1

x = 7 + 27

Decimal Notation

x = 12.29150 \dots

Solution steps

2 x - 3 - x + 1 = 1

Remove square roots

x^{2} - 10 x + 25 = 4 x + 4

Solve

x^{2} - 10 x + 25 = 4 x + 4 : x = 7 + 27, x = 7 - 27

x = 7 + 27, x = 7 - 27

Verify Solutions:

x = 7 + 27

True

, x = 7 - 27

False

The solution is

x = 7 + 27

6 - (2 x + 5)^{\frac{1}{2}} = 0

2 b + 5 = 3

5 = 0.7 A^{0.3}

z, 7 - 3 z = 3 + cz

What is the answer to sqrt(2x-3)-sqrt(x+1)=1 ?
The answer to sqrt(2x-3)-sqrt(x+1)=1 is x=7+2sqrt(7)
Solve for x: sqrt(2x-3)-sqrt(x+1)=1
The solution is x=7+2sqrt(7)