What is the answer to solvefor x,(1+x)^{15.6}=2 ?

The answer to solvefor x,(1+x)^{15.6}=2 is x=2^{5/78}-1

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solvefor x,(1+x)^{15.6}=2

x, (1 + x)^{15.6} = 2

x = 2^{\frac{5}{78}} - 1

Decimal Notation

x = 0.04543 \dots

Solution steps

(1 + x)^{15.6} = 2

Take both sides of the equation to the power of

\frac{5}{78} : (1 + x) = 2^{\frac{5}{78}}

(1 + x) = 2^{\frac{5}{78}}

Solve

(1 + x) = 2^{\frac{5}{78}} : x = 2^{\frac{5}{78}} - 1

x = 2^{\frac{5}{78}} - 1

Verify Solutions:

x = 2^{\frac{5}{78}} - 1

True

The solution is

x = 2^{\frac{5}{78}} - 1

1 = \frac{3}{x} - 2

x^{2} + x - 6 x - 8 = 0

4 - 5 x = 12

x + 5 x + 6 = 0

2 v + 13 = v + 7

What is the answer to solvefor x,(1+x)^{15.6}=2 ?
The answer to solvefor x,(1+x)^{15.6}=2 is x=2^{5/78}-1