What are the solutions to the equation 7r^2-14r=-7 ?

The solutions to the equation 7r^2-14r=-7 are r=1

Find the zeros of 7r^2-14r=-7

The zeros of 7r^2-14r=-7 are r=1

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7 r^{2} - 14 r = - 7

r = 1

Solution steps

7 r^{2} - 14 r = - 7

Move

7

to the left side

7 r^{2} - 14 r + 7 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 7 \cdot 7}{2 \cdot 7}

(- 14)^{2} - 4 \cdot 7 \cdot 7 = 0

r_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 7}

r = \frac{- ( - 14 )}{2 \cdot 7}

\frac{- ( - 14 )}{2 \cdot 7} = 1

r = 1

The solution to the quadratic equation is:

r = 1

x^{2} + 18 x = 0

14 = 4 + 27 t - 16 t^{2}

∣ x - 2 ∣ - 4 > 0

2 (3 x + 1) - 2 (x - \frac{7}{2}) = x + 12

What are the solutions to the equation 7r^2-14r=-7 ?
The solutions to the equation 7r^2-14r=-7 are r=1
Find the zeros of 7r^2-14r=-7
The zeros of 7r^2-14r=-7 are r=1