What is the answer to sqrt(2w^2-19w+31)+2=7-2w ?

The answer to sqrt(2w^2-19w+31)+2=7-2w is w=-3/2 ,w=2

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sqrt(2w^2-19w+31)+2=7-2w

2 w^{2} - 19 w + 31 + 2 = 7 - 2 w

w = - \frac{3}{2}, w = 2

Decimal Notation

w = - 1.5, w = 2

Solution steps

2 w^{2} - 19 w + 31 + 2 = 7 - 2 w

Remove square roots

2 w^{2} - 19 w + 31 = 4 w^{2} - 20 w + 25

Solve

2 w^{2} - 19 w + 31 = 4 w^{2} - 20 w + 25 : w = - \frac{3}{2}, w = 2

w = - \frac{3}{2}, w = 2

Verify Solutions:

w = - \frac{3}{2}

True

, w = 2

True

The solutions are

w = - \frac{3}{2}, w = 2

2 x - 6 x + 4 = 0

2 x + 3 = 4

2 x + 3 = 6

2 x + 3 = 8

\frac{1}{- x} = 1

What is the answer to sqrt(2w^2-19w+31)+2=7-2w ?
The answer to sqrt(2w^2-19w+31)+2=7-2w is w=-3/2 ,w=2
Solve for w: sqrt(2w^2-19w+31)+2=7-2w
The solution is w=-3/2 ,w=2