What is the answer to sqrt(x+3)=2x+1 ?

The answer to sqrt(x+3)=2x+1 is x=(-3+sqrt(41))/8

Solve for x: sqrt(x+3)=2x+1

The solution is x=(-3+sqrt(41))/8

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x + 3 = 2 x + 1

x = \frac{- 3 + 41}{8}

Decimal Notation

x = 0.42539 \dots

Solution steps

x + 3 = 2 x + 1

Square both sides:

x + 3 = 4 x^{2} + 4 x + 1

x + 3 = 4 x^{2} + 4 x + 1

Solve

x + 3 = 4 x^{2} + 4 x + 1 : x = \frac{- 3 + 41}{8}, x = \frac{- 3 - 41}{8}

x = \frac{- 3 + 41}{8}, x = \frac{- 3 - 41}{8}

Verify Solutions:

x = \frac{- 3 + 41}{8}

True

, x = \frac{- 3 - 41}{8}

False

The solution is

x = \frac{- 3 + 41}{8}

x + 9 - x - 2 = 1

6 - 2 x - 2 x - 1 = 1

x + 8 - x - 1 = 1

3 - 2 x = 2 x + 3

What is the answer to sqrt(x+3)=2x+1 ?
The answer to sqrt(x+3)=2x+1 is x=(-3+sqrt(41))/8
Solve for x: sqrt(x+3)=2x+1
The solution is x=(-3+sqrt(41))/8