What is the answer to 6=sqrt(x^2+3-x) ?

The answer to 6=sqrt(x^2+3-x) is x=(1+sqrt(133))/2 ,x=(1-sqrt(133))/2

Solve for x: 6=sqrt(x^2+3-x)

The solution is x=(1+sqrt(133))/2 ,x=(1-sqrt(133))/2

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6 = x^{2} + 3 - x

x = \frac{1 + 133}{2}, x = \frac{1 - 133}{2}

Decimal Notation

x = 6.26628 \dots, x = - 5.26628 \dots

Solution steps

6 = x^{2} + 3 - x

Square both sides:

36 = x^{2} + 3 - x

36 = x^{2} + 3 - x

Solve

36 = x^{2} + 3 - x : x = \frac{1 + 133}{2}, x = \frac{1 - 133}{2}

x = \frac{1 + 133}{2}, x = \frac{1 - 133}{2}

Verify Solutions:

x = \frac{1 + 133}{2}

True

, x = \frac{1 - 133}{2}

True

The solutions are

x = \frac{1 + 133}{2}, x = \frac{1 - 133}{2}

x = 9 x + 4

x^{2} - x - 9 = x + 3

x^{2} - x - 9 = x + 5

49 - x^{2} = 0

13 = (4 x + 2)

What is the answer to 6=sqrt(x^2+3-x) ?
The answer to 6=sqrt(x^2+3-x) is x=(1+sqrt(133))/2 ,x=(1-sqrt(133))/2
Solve for x: 6=sqrt(x^2+3-x)
The solution is x=(1+sqrt(133))/2 ,x=(1-sqrt(133))/2