What are the solutions to the equation 4x^2+4x-63=0 ?

The solutions to the equation 4x^2+4x-63=0 are x= 7/2 ,x=-9/2

Find the zeros of 4x^2+4x-63=0

The zeros of 4x^2+4x-63=0 are x= 7/2 ,x=-9/2

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4 x^{2} + 4 x - 63 = 0

x = \frac{7}{2}, x = - \frac{9}{2}

Decimal Notation

x = 3.5, x = - 4.5

Solution steps

4 x^{2} + 4 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 63 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 63) = 32

x_{1, 2} = \frac{- 4 \pm 32}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 32}{2 \cdot 4}, x_{2} = \frac{- 4 - 32}{2 \cdot 4}

x = \frac{- 4 + 32}{2 \cdot 4} : \frac{7}{2}

x = \frac{- 4 - 32}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{9}{2}

\frac{3}{2} \cdot 4

\frac{1}{2} \cdot 20

(\frac{f}{g}) (x)

\frac{x + 2}{3} + 2 = \frac{x + 4}{6}

(625 x)^{\frac{3}{4}}

What are the solutions to the equation 4x^2+4x-63=0 ?
The solutions to the equation 4x^2+4x-63=0 are x= 7/2 ,x=-9/2
Find the zeros of 4x^2+4x-63=0
The zeros of 4x^2+4x-63=0 are x= 7/2 ,x=-9/2